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Volume occupied by one molecule of water (density = 1 g cm^(3))
Assuming the density of water to be 1 g/ml, calculate the volume occupied by one molecule of water.
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The volume of water molecule is Take, density of wter is 10^(3) kg m^(-3) and avogadros' number =610^(23) "mole"^(-1))
How many water molecules are there in a drop of volume 0.05 mL? (Density of water is 1 g/mL)
SOLVED: Question 9 1pts The volume of a single molecule of water is 2.99 * 10-23 mL.For a sample of gaseous water at 1.00 atm and 150 %C,what fraction of the container's
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Volume occupied by one molecule of water ( density = 1 g cm^-3 ) is
Calculate (i) the volume of one molecule of water. (ii) the radius of a water molecule assuming the molecule to be spherical. (Given that the density of water is 1 g/cm^3.
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Volume occupied by one molecule of water (density= 1 g cm⁻³) is - NEETLab
![Volume occupied by one molecule of water is:[density = 1 g cm^-3]](https://dwes9vv9u0550.cloudfront.net/images/11787771/5012c0ab-92d4-445f-8570-631fbb87fc75.jpg "Volume occupied by one molecule of water is:[density = 1 g cm^-3]")
Volume occupied by one molecule of water is:[density = 1 g cm^-3]
Assuming the density of water to be 1 g/ml, calculate the volume occupied by one molecule of water.
Helmholtz free energy normalized on water molecule number dependence on... | Download Scientific Diagram
Volume occupied by one molecule of water (density = 1g cm3 - Brainly.in
