![SOLVED: Let f(z) be continuous everywhere and consider the function g(z). If f(z) > 0, then g(z) = f(z). If f(z) < 0, then g(z) = -f(z). Prove that g(z) is continuous SOLVED: Let f(z) be continuous everywhere and consider the function g(z). If f(z) > 0, then g(z) = f(z). If f(z) < 0, then g(z) = -f(z). Prove that g(z) is continuous](https://cdn.numerade.com/ask_images/9d39ffe311004d7cb1e3d7d4115a52d0.jpg)
SOLVED: Let f(z) be continuous everywhere and consider the function g(z). If f(z) > 0, then g(z) = f(z). If f(z) < 0, then g(z) = -f(z). Prove that g(z) is continuous
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real analysis - Proving that the inverse of a bijective continuous function is continuous - Mathematics Stack Exchange
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epsilon delta - Help needed in the details of proving continuity for the function $f(x)=\frac{1}{x^2}$ on $(0,\infty)$ - Mathematics Stack Exchange
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real analysis - Proving the continuity of a function at a given point - help needed - Mathematics Stack Exchange
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